If it's not what You are looking for type in the equation solver your own equation and let us solve it.
6x^2+10=-17x
We move all terms to the left:
6x^2+10-(-17x)=0
We get rid of parentheses
6x^2+17x+10=0
a = 6; b = 17; c = +10;
Δ = b2-4ac
Δ = 172-4·6·10
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-7}{2*6}=\frac{-24}{12} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+7}{2*6}=\frac{-10}{12} =-5/6 $
| -7x+67+30=180 | | x+(4x10)=180 | | 14.9=d+8.1 | | 12x²-36x+27=0 | | -2(x-3)=5(2x/3) | | 7+10x+3=120 | | 3(4x²-6x+9)=0 | | 370=18z | | N+40=6n-5 | | -2.3+x4=-8.7 | | -32x+8=-80+-32x+8=16 | | 5a–35=60 | | -32+8y=-80+-32+8y=16 | | -2/3x+9=4/3x | | -x+17=612 | | -2.3+v4=-8.7 | | x+2=15/6+x/12 | | -2r^2-3r-3=0 | | 3+v=4v-v | | 4p+27=91 | | 4(z+7)=52 | | (5^x)^3=25 | | z/3+26=35 | | -5m+2(3m-3)=12 | | -3+m/9=2 | | 11-x=75-(-1) | | t/2-9=6 | | x(7-6x)=0 | | h/6+24=27 | | 12^x+10=13^8x | | x(7+6x)=0 | | 5b-7=28 |